This is very interesting. Best of luck to the Rockies
NEW YORK - Here’s a scenario that could mess up baseball’s postseason schedule: Imagine if Arizona, Colorado, the New York Mets, Philadelphia and San Diego finish with the same record.
That would create ties in the NL East, NL West and wild card race, necessitating four days of tiebreaker games to determine postseason berths.
The NL East is the easiest: The Mets would play Monday at Philadelphia.
In the West, the team with the best head-to-head record against the others (because Arizona plays Colorado this weekend, that’s yet to be determined), gets to choose whether it prefers one tiebreaker road game or two home games. Presumably, the team with the choice would take one road game. Monday’s winner would then host the club with the bye on Tuesday.
Starting Wednesday, the three teams that failed to win division titles would be involved in a two-day, two-game tiebreakers to determine the wild card winner.
Yesterday, a coin flip was held in case the Mets wind up in a tie for the wild card. The Mets would host Arizona and San Diego, but would play at Colorado.
Arizonawent 0-4 in wild-card coin flips and also would be on the road at Colorado, Philadelphia and San Diego.
Flips held Sept. 7 determined that the Mets would be at the Phillies if they tie for the NL East. In the NL West, Colorado and San Diego would be at Arizona, and Colorado would be at San Diego.
In the wild card race, Philadelphia would be at Colorado and San Diego, and the Padres would be at Colorado.